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a(n) = b(0)!*b(1)!*...*b(n)! + 1 where b() = sequence A094351.
1

%I #13 Sep 17 2024 14:48:55

%S 2,2,3,13,8641,3135283201,11377315676160001,57341671007846400001,

%T 507001407374702050423176181238467028582400000000001,

%U 12168033776992849210156228349723208685977600000000001

%N a(n) = b(0)!*b(1)!*...*b(n)! + 1 where b() = sequence A094351.

%C All terms are prime by the definition of A094351.

%C The next prime has 109 digits. - _Jinyuan Wang_, Mar 03 2020

%e a(4) = 8641 = 1!*2!*3!*6! + 1.

%Y Cf. A094351.

%K nonn

%O 0,1

%A _Amarnath Murthy_, May 22 2004

%E Name clarified by, offset changed to 0 by and more terms from _Jinyuan Wang_, Mar 03 2020