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a(n) = 6 written in base n.
3

%I #14 Jun 16 2024 05:22:01

%S 111111,110,20,12,11,10,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,

%T 6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,

%U 6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6,6

%N a(n) = 6 written in base n.

%C The term 111....1111 should officially be called the "unary expansion", since in base 1 only the digit 0 may appear.

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (1).

%F From _Elmo R. Oliveira_, Jun 15 2024: (Start)

%F G.f.: x*(111111-111001*x-90*x^2-8*x^3-x^4-x^5-4*x^6)/(1-x).

%F a(n) = 6 for n > 6. (End)

%Y Cf. A001734, A063432, A035613, A094324, A094326, A094327, A094232, etc.

%K nonn,base,easy

%O 1,1

%A _N. J. A. Sloane_, Jun 04 2004