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%I #14 Mar 05 2024 16:31:31
%S 1,6,21,93,698,5377,48198,483817,5231438,61160870,774696437,
%T 10552025533,153901234789
%N Smallest integers at which the value of truncated Mertens function equals n!.
%C Observe that magnitude of a(n) is not far from that of (n-1)!.
%F Solutions to Min(x : A088004(x) = n!), i.e., a(n) = Min(x : A002321(x) + A000720(x) = n!).
%t s = 0; k = 1; Do[ While[s = s + MoebiusMu[k]; s + PrimePi[k] < n!, k++ ]; Print[k]; k++, {n, 10}] (* _Robert G. Wilson v_, Apr 30 2004 *)
%Y Cf. A002321, A000720, A088004, A093772, A093773.
%K nonn,more
%O 1,2
%A _Labos Elemer_, Apr 28 2004
%E a(9)-a(10) from _Robert G. Wilson v_, Apr 30 2004
%E a(11)-a(13) from _Donovan Johnson_, Jun 21 2012