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Define the divisor symmetry of a number n to be k if n-r and n+r have the same number of divisors for r = 1 to k but not for k+1. Sequence contains the divisor symmetry of n.
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%I #11 Jul 15 2018 13:06:55

%S 0,0,0,1,0,1,1,0,2,0,0,2,0,0,0,0,0,1,1,0,0,0,0,0,0,0,0,0,0,4,0,0,0,1,

%T 0,0,0,0,0,0,1,1,0,0,0,0,0,0,0,0,1,0,0,0,1,1,0,0,0,2,0,0,0,0,0,0,0,0,

%U 0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,0,0,1,1,0,0

%N Define the divisor symmetry of a number n to be k if n-r and n+r have the same number of divisors for r = 1 to k but not for k+1. Sequence contains the divisor symmetry of n.

%C Subsidiary sequence: Index of the first occurrence of n in this sequence.

%C Is this sequence bounded? Through n = 20000, a(432)=6 is the only value greater than 4. - _Franklin T. Adams-Watters_, May 12 2006

%C I conjecture that the sequence is unbounded. [_Charles R Greathouse IV_, Dec 19 2011]

%H Charles R Greathouse IV, <a href="/A093492/b093492.txt">Table of n, a(n) for n = 1..10000</a>

%Y Cf. A202463, A093493, A093494, A093488, A093491.

%K nonn

%O 1,9

%A _Amarnath Murthy_, Apr 16 2004

%E More terms from _Franklin T. Adams-Watters_, May 12 2006