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Numerator of I(n) = Integral_{x=0..1/(4^n)} (1-sqrt(x))^2 dx; e.g., I(3) = 323/24576. The denominator is b(n) = 96*16^(n-1); e.g., b(3) = 24576.
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%I #19 Aug 18 2019 02:50:26

%S 1,11,67,323,1411,5891,24067,97283,391171,1568771,6283267,25149443,

%T 100630531,402587651,1610481667,6442188803,25769279491,103078166531,

%U 412314763267,1649263247363,6597061378051,26388262289411

%N Numerator of I(n) = Integral_{x=0..1/(4^n)} (1-sqrt(x))^2 dx; e.g., I(3) = 323/24576. The denominator is b(n) = 96*16^(n-1); e.g., b(3) = 24576.

%F Empirical g.f.: (1 + 4*x + 4*x^2)/(1 - 7*x + 14*x^2 - 8*x^3). [_Colin Barker_, Jan 01 2012]

%p J:=n->int((1-sqrt(x))^2,x=0..1/4^n): seq(numer(J(n)),n=0..25); # _Emeric Deutsch_, Feb 23 2005

%K nonn,frac,easy

%O 0,2

%A Al Hakanson (hawkuu(AT)excite.com), Apr 15 2004

%E More terms from _Emeric Deutsch_, Feb 23 2005