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%I #11 Nov 19 2017 12:55:14
%S 1,8,207,40,7520,38880,2050496,14680064,983222784,9000000000,
%T 733008370688,8173092077568,784798672805888,10318292052303872,
%U 1141809497781288960,1025031833202524160,2183733606400887160832
%N Least multiple of n such that the n-th partial sum is an n-th power with the condition that a(n+1) exists.
%e a(2) = 8, yielding the 2nd partial sum 1 + 8 = 9 = 3^2.
%e a(3) cannot be j^3 - 9 for j = 3, 4, or 5, because there would be no number k such that j^3 + 4k = is a 4th power; thus, a(3) = 207, yielding the 3rd partial sum 9 + 207 = 216 = 6^3 (and a(4) = 4^4 - 6^3 = 40).
%Y Cf. A090963.
%K nonn
%O 1,2
%A _Amarnath Murthy_, Jan 02 2004
%E More terms from _David Wasserman_, Feb 23 2006
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