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A090523
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Smallest prime p such that floor(n!/p) is prime, or 0 if no such prime exists.
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1
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0, 0, 2, 7, 7, 19, 29, 17, 107, 29, 151, 67, 101, 31, 43, 163, 59, 31, 41, 173, 79, 167, 73, 233, 107, 73, 29, 43, 1259, 89, 317, 191, 349, 541, 199, 173, 577, 89, 373, 997, 197, 773, 1093, 257, 1733, 487, 349, 149, 1511, 2621, 389, 181, 151
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OFFSET
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1,3
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COMMENTS
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Conjecture: There are no zeros for n > 2.
This conjecture is correct. For m > 1, there is always a prime between m and 2*m. Taking m = n!/4, this gives us a prime p such that floor(n!/p) = 2 or 3. - Franklin T. Adams-Watters, Jul 28 2011
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LINKS
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MATHEMATICA
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Do[p = 1; While[ !PrimeQ[Floor[n!/Prime[p]]], p++ ]; Print[Prime[p]], {n, 3, 30}] (* Ryan Propper, Jun 23 2005 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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