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A090512 Least multiple of n such that the n-th concatenation is a multiple of n. The (previous) (n-1)-th term is so chosen that the n-th term exists. 0
1, 2, 3, 12, 15, 30, 7, 128, 9, 50, 22, 36, 26, 28, 15, 1232, 85, 414, 19, 500, 84, 462, 69, 120, 200, 364, 81, 532, 29, 810, 31, 10784, 198, 272, 70, 1476, 148, 266, 39, 2160, 123, 1890, 43, 308, 855, 368, 94, 336, 49, 1550, 153, 52, 1484, 648, 220, 3416, 1026, 3886 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
If n+1 has any prime divisors other than 2 or 5, then a(n) is to be chosen so that the concatenation of first n terms is a multiple of those primes (including multiplicity). - David Wasserman, Dec 20 2005
LINKS
EXAMPLE
a(5) = 15 because if it were 5 or 10, a(6) would not exist.
CROSSREFS
Sequence in context: A173079 A173903 A154785 * A076175 A289870 A067780
KEYWORD
base,nonn
AUTHOR
Amarnath Murthy, Dec 06 2003
EXTENSIONS
More terms from David Wasserman, Dec 20 2005
STATUS
approved

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Last modified June 19 12:43 EDT 2024. Contains 373503 sequences. (Running on oeis4.)