A088774 - OEIS

%I #12 Mar 07 2021 01:09:05

%S 11,11,101,10001,99775226

%N a(n) = A082779(n+1)/A082779(n).

%C a(n)<=10^A055642(A082779(n))+1. If A082779(n) > 10 and the last digit of A082779(n) <= 4, then a(n)<=10^(A055642(A082779(n))-1)+1. - _Chai Wah Wu_, Mar 06 2021

%Y Cf. A082779.

%Y Cf. A088771, A088772, A088773, A088775, A088776, A088777, A088778, A088779.

%K base,nonn,more

%O 1,1

%A _Ray Chandler_, Oct 26 2003

%E Corrected a(5) and removed possibly erroneous a(6) by _Chai Wah Wu_, Mar 06 2021