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%I #16 Nov 25 2024 00:55:32
%S 11,11,101,10001,99775226,10000000000000001
%N a(n) = A082779(n+1)/A082779(n).
%C a(n)<=10^A055642(A082779(n))+1. If A082779(n) > 10 and the last digit of A082779(n) <= 4, then a(n)<=10^(A055642(A082779(n))-1)+1. - _Chai Wah Wu_, Mar 06 2021
%Y Cf. A082779.
%Y Cf. A088771, A088772, A088773, A088775, A088776, A088777, A088778, A088779.
%K base,nonn,more
%O 1,1
%A _Ray Chandler_, Oct 26 2003
%E Corrected a(5) and removed possibly erroneous a(6) by _Chai Wah Wu_, Mar 06 2021
%E a(6) from _Max Alekseyev_, Nov 24 2024