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Value of n-th digit in ternary representation of n^n.
7

%I #3 Mar 30 2012 18:50:38

%S 1,0,0,1,0,0,1,1,1,0,0,0,1,2,1,2,2,0,0,1,1,1,0,2,1,1,0,0,1,0,1,1,1,2,

%T 0,2,0,2,1,1,1,0,1,0,1,0,0,0,1,2,2,2,1,1,0,1,2,1,1,1,1,1,1,0,0,1,1,0,

%U 2,2,1,0,0,0,0,1,1,2,1,2,1,0,0,1,1,0,2,2,0,0,0,2,1,1,0,0,1,2,0,0,1,1

%N Value of n-th digit in ternary representation of n^n.

%C a(n)=d(n) with n^n = Sum(d(k)*3^k: 0<=d(k)<3, k>=0).

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/Ternary.html">Ternary</a>

%F a(n) = floor(n^n / 3^n) mod 3.

%e n=7, 7^7=3110367 -> '1112211200121', '111221-------': a(7)=1.

%Y Cf. A007089, A000312, A088150, A088152, A088153, A088154, A088155, A088156, A088157.

%K nonn,base

%O 0,14

%A _Reinhard Zumkeller_, Sep 20 2003