

A088023


Set a(1) = 1. Then take the list of defined initial terms, reverse their order, add 1, 2, 3, ... to the reversed list in succession and append this new list to the right of the previously defined terms. Repeat this process indefinitely.


3



1, 2, 3, 3, 4, 5, 5, 5, 6, 7, 8, 8, 8, 9, 9, 9, 10, 11, 12, 12, 13, 14, 14, 14, 14, 15, 16, 16, 16, 17, 17, 17, 18, 19, 20, 20, 21, 22, 22, 22, 23, 24, 25, 25, 25, 26, 26, 26, 26, 27, 28, 28, 29, 30, 30, 30, 30, 31, 32, 32, 32, 33, 33, 33
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OFFSET

1,2


COMMENTS

Conjecture: a(n+1) >= a(n). Comments from Don Reble, Nov 13 2005: The conjecture is plainly true. In fact, a(n+1)a(n) = 0 or 1. Also a(A091072(n)) = n; a(A091072(n)+1) = n+1.


LINKS

Table of n, a(n) for n=1..64.


FORMULA

a(n)=2a(n/2)1 if a=2^k else a(n)=a(2^kn+1)+n2^(k1) if 2^(k1)<n<2^k. (Ed.)


EXAMPLE

The sequence begins 1, 2, then reverse 1, 2 = 2, 1 then add 1, 2 to the latter getting 3, 3. Then append 3, 3, to the right of 1, 2, getting 1, 2, 3, 3. Then repeating the instructions, 1, 2, 3, 3 is reversed then add 1, 2, 3, 4 to 3, 3, 2, 1, = 4, 5, 5, 5. Append the latter to 1, 2, 3, 3 getting 1, 2, 3, 3, 4, 5, 5, 5, ...; and so on.


CROSSREFS

Sequence in context: A242453 A241151 A073092 * A324477 A287292 A260717
Adjacent sequences: A088020 A088021 A088022 * A088024 A088025 A088026


KEYWORD

nonn


AUTHOR

Gary W. Adamson, Sep 19 2003


EXTENSIONS

Edited by John W. Layman, Oct 10 2003


STATUS

approved



