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Partial quotients of the continued fraction of sqrt(2), having 8 as the constant numerator: sqrt(2) = a(0) + 8/(a(1) + 8/(a(2) + 8/(a(3) +...))).
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%I #3 Mar 30 2012 18:36:38

%S 1,19,25,15,8,21,11,12,8,83,14,27,44,39,12,43,18,9,8,80,9,12,17,53,8,

%T 39,8,53,37,79,399,12,23,35,14,17,57,8,26,29,19,9,12,18,14,81,11,8,22,

%U 8,15,12,27,568,19,12,15,17,14,8,26,227,65,8,27,10,25,11,14,16,55,10,11,23

%N Partial quotients of the continued fraction of sqrt(2), having 8 as the constant numerator: sqrt(2) = a(0) + 8/(a(1) + 8/(a(2) + 8/(a(3) +...))).

%C These partial quotients are not periodic. The number 8 is the first constant numerator that does not produce periodic partial quotients for sqrt(2); see A087950.

%Y Cf. A087950.

%K nonn

%O 0,2

%A _Paul D. Hanna_, Sep 16 2003