

A087139


Least k>1 such that p^k  p^(k1) + 1 is prime for p = prime(n).


3



2, 2, 3, 2, 11, 2, 5, 30, 15, 3, 6, 10, 81, 3, 17, 961, 15, 7, 2, 5, 6, 2, 3, 3, 12, 3, 57, 5, 16, 5, 166, 15, 13, 2, 3, 2, 30, 2, 25, 3, 47, 3, 3, 2, 521, 9, 3, 15, 17, 42, 17, 51, 39
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OFFSET

1,1


COMMENTS

The next term in this sequence, a(54) for the prime p=251, is greater than 73000.
Is there a prime p such that p^k  p^(k1) + 1 is composite for all k > 1? For the related question of Sierpinski numbers (n such that n*2^k+1 is composite for all k ), the answer is yes.
If n=251^k251^(k1)+1 is prime then k mod 10 = 1,5,7 or 9 because n mod 3 = 0 iff k is even and n mod 11 = 0 iff k mod 5 = 3. More exponents can be cleared this way.  Bernardo Boncompagni, Oct 23 2005
Note that k cannot be 8, 14, 20, ... (i.e. k == 2 mod 6) because then p^2  p + 1 divides p^k  p^(k1) + 1.  T. D. Noe, Aug 31 2006


REFERENCES

See A087126.


LINKS

Table of n, a(n) for n=1..53.


MATHEMATICA

lst={}; Do[p=Prime[n]; i=2; While[m=p^ip^(i1)+1; !PrimeQ[m], i++ ]; AppendTo[lst, i], {n, 53}]; lst


CROSSREFS

Cf. A040076 (Sierpinski numbers), A087126 (primes of the form p^k  p^(k1) + 1).
Cf. A122396.
Sequence in context: A098189 A162733 A016003 * A342607 A226422 A016005
Adjacent sequences: A087136 A087137 A087138 * A087140 A087141 A087142


KEYWORD

more,nonn


AUTHOR

T. D. Noe, Aug 18 2003


STATUS

approved



