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%I #3 Mar 30 2012 18:50:37
%S 1,2,3,3,4,3,4,4,6,4,6,5,2,3,5,3,6,6,8,5,4,7,2,4,8,6,8,7,3,7,5,5,6,10,
%T 6,10,7,5,7,7,7,8,8,9,4,9,5,8,10,8,11,2,5,9,6,11,3,8,12,7,9,7,10,9,8,
%U 13,2,6,12,8,14,8,15,6,13,3,9,9,10,10,11,4,10,12,9,11,5,10,13,4,11,6
%N a(1) = 1; a(n+1) = a(n)/spf(a(n)) + number of earlier occurrences of a(n), spf=A020639 = smallest prime factor.
%e n=11: a(10) = 4 and a(9) = a(6) = 4, therefore a(11) =
%e a(10)/spf(a(10))+3 = 4/spf(4)+3 = 2+3 = 5.
%K nonn
%O 1,2
%A _Reinhard Zumkeller_, Sep 20 2003