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%I #6 Jan 27 2020 18:48:49
%S 1,6,82377,29621978134,55110944435590737,351365336651946711055926,
%T 6008600239785614025435195490441,
%U 234070069565049957790986633184065559782,18482397400123127114222085701577635920656730209,2709724243821243799193362741406845754919489407774774182
%N a(n) = 1/5!*(A000522(5*n)+10*A000522(3*n)+20*A000522(2*n)+45*A000522(n)+44).
%H Andrew Howroyd, <a href="/A086897/b086897.txt">Table of n, a(n) for n = 0..50</a>
%o (PARI) \\ here b(n) is A000522(n).
%o b(n)={sum(k=0, n, binomial(n, k)*k!)}
%o a(n)={(b(5*n) + 10*b(3*n) + 20*b(2*n) + 45*b(n) + 44) / 120} \\ _Andrew Howroyd_, Jan 27 2020
%Y Cf. A000522, A008290.
%K nonn
%O 0,2
%A _Vladeta Jovovic_, Aug 22 2003
%E Terms a(8) and beyond from _Andrew Howroyd_, Jan 27 2020
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