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%I #4 Oct 01 2013 17:57:39
%S 14,5,5,11,10,3,6,13,26,9,13,2,3,12,9,4,15,4,24,19,5,19,4,11,9,1,1,1,
%T 1,1,23,18,4,40,4,7,9,13,14,16,6,9,5,16,3,4,9,12,3,11,18,14,14,27,3,
%U 11,4,6,12,6,7,34,48,9,7,4,7,11,9,16,12,50,9,7,18,5,6,34,1,1,1,1,1,1,1,3,8
%N Position of the first zero in the decimal expansion of the square root of the n-th prime.
%e sqrt(1213) = 34.82814953453599722269575212191436263382649518168323557106085786016708, first zero is at position 57.
%o (PARI) \ zeros in sqrt(p) where p is prime. frootp(n) = { default(realprecision,100); forprime(x=2,n, r = sqrt(x); \ print(x" "r); v = Vec(Str(r)); c=-1; for(y=1,100, c++; if(v[y] == "0",print1(c","); break) ) ) }
%Y Cf. A074850.
%K easy,nonn,base
%O 1,1
%A _Cino Hilliard_, Jun 29 2003
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