OFFSET
1,3
COMMENTS
If n contains all odd digits then a(n+1) = 0. If n+1 is not divisible by 5 and n contains an even digit then a(n+1) is nonzero. Infinitely many triples of successive zeros are there.
It's not clear whether or not a digit that occurs twice in n-1 is required to occur twice in a(n). The first time it matters is a(101), which is either 101 or 1010. - David Wasserman, Dec 03 2004
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Amarnath Murthy, May 20 2003
EXTENSIONS
Corrected and extended by David Wasserman, Dec 03 2004
STATUS
approved