%I #14 Sep 24 2018 16:53:14
%S 1,2,3,4,5,6,7,8,9,22,11,44,101,33,55,14641,131,99,151,171,77,111,181,
%T 88,121,141,343,212,191,66,313,0,161,202,262,484,353,303,323,232,373,
%U 222,383,242,292,393,727,272,10201,333,454,363,757,424,505,686,515,535
%N a(n) = smallest palindrome not included earlier and with the same prime signature as n, or 0 if no such palindrome exists.
%C Conjecture: There are infinitely many zeros in this sequence.
%C a(32) = 0 is only a conjecture. If there is a palindromic 5th power, it is greater than 10^40. - _David Wasserman_, Mar 22 2005
%e 16 = 2^4 which has the prime signature p^4, p a prime; hence a(16) = 14641= 11^4 has the prime signature p^4.
%e a(30) = 66 as 66 and 30 have same prime signature.
%e a(18) = 99, as 44 with the same prime signature is already included as a(12)=44.
%K base,nonn
%O 1,2
%A _Amarnath Murthy_ and Meenakshi Srikanth (menakan_s(AT)yahoo.com), Apr 29 2003
%E Corrected and extended by _Ray Chandler_, Sep 05 2003
%E Edited by _N. J. A. Sloane_ at the suggestion of _Andrew S. Plewe_, Jun 11 2007