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a(n) = (4*n^n + (n-10)^n)/5.
2

%I #12 Sep 08 2022 08:45:10

%S 1,-1,16,-47,464,1875,38144,658397,13421824,309936391,8000000000,

%T 228249336489,7132880359424,242300085592667,8889605514133504,

%U 350315118408203125,14757395823189622784,661792256035172208783,31477130063116931956736

%N a(n) = (4*n^n + (n-10)^n)/5.

%H Vincenzo Librandi, <a href="/A083307/b083307.txt">Table of n, a(n) for n = 0..300</a>

%o (Magma) [(4*n^n+(n-10)^n)/5: n in [0..25]]; // _Vincenzo Librandi_, Jun 29 2011

%o (PARI) a(n)=(4*n^n+(n-10)^n)/5 \\ _Charles R Greathouse IV_, Jun 29 2011

%Y Cf. A083308.

%K easy,sign

%O 0,3

%A _Paul Barry_, Apr 24 2003