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Bases for the cubes arising in A083203.
4

%I #10 Jan 08 2019 09:12:41

%S 2,4,7,11,16,22,9,17,289,1873,11553,63553,4573699,14073021495,

%T 65713427547321843,57325015297059875497553701478

%N Bases for the cubes arising in A083203.

%F a(n) = [A083203(n)*A083203(n+1)+1]^(1/3). - _R. J. Mathar_, Feb 05 2007

%e a(1)=2 since A083203(1)*A083203(2)+1=1*7+1=8=2^3.

%Y Cf. A083203.

%K more,nonn

%O 1,1

%A _Amarnath Murthy_, Apr 28 2003

%E Corrected and extended by _Vladeta Jovovic_, May 01 2003

%E More terms from _Michel ten Voorde_ Jun 23 2003

%E More terms from _R. J. Mathar_, Feb 05 2007