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a(n) = (Sum of the terms of A083164 with index which are the divisors of n ) /n.
3

%I #8 Apr 17 2015 15:23:50

%S 1,2,1,2,2,2,2,2,2,2,1,3,1,2,2,2,2,3,2,3,1,2,1,3,2,3,3,2,2,2,2,2,2,2,

%T 2,4,2,2,3,3,2,2,1,3,2,3,1,3,3,3,3,3,2,4,3,2,1,2,1,3,2,2,3,2,2,3,3,3,

%U 1,2,1,5,1,2,2,3,2,4,1,3,3,2,1,3,2,2,2,4,1,3,1,3,1,2,2,4,1,4,3,3,1,3,2,4,2

%N a(n) = (Sum of the terms of A083164 with index which are the divisors of n ) /n.

%H Paul Tek, <a href="/A083165/b083165.txt">Table of n, a(n) for n = 1..10000</a>

%e a(12)= 3 = (1+3+2+4+6+20)/12 = 36/12=3. where 1,3,2,4,6 and 20 are the first,2nd,3rd,4th,6th and 12th terms of A083164.

%Y Cf. A083164, A083166.

%K nonn

%O 1,2

%A _Amarnath Murthy_, Apr 26 2003

%E More terms from _David Wasserman_, Oct 22 2004