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a(1)=1, a(n)=a(floor(n/2))+a(floor(n/3)).
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%I #5 Mar 30 2012 18:39:17

%S 1,2,2,3,3,4,4,5,5,5,5,7,7,7,7,8,8,9,9,9,9,9,9,12,12,12,12,12,12,12,

%T 12,13,13,13,13,16,16,16,16,16,16,16,16,16,16,16,16,20,20,20,20,20,20,

%U 21,21,21,21,21,21,21,21,21,21,22,22,22,22,22,22,22,22,28,28,28,28,28,28

%N a(1)=1, a(n)=a(floor(n/2))+a(floor(n/3)).

%F a(n)*log(n)/n is bounded.

%o (PARI) a(n)=if(n<2,1,a(floor(n/2))+a(floor(n/3)))

%K nonn

%O 1,2

%A _Benoit Cloitre_, Apr 27 2003