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Let f(x,y)=floor((1+1/y)^x); sequence gives least k such that f(k+2,n)/f(k,n)=(1+1/n)^2.
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%I #5 Mar 30 2012 18:39:16

%S 1,36,20,117,37,42,70,68,57,139,186,149,119,542,389,135,328,297,327,

%T 1055,299,273,782,328,1117,445,1916,1951,493,1148,1238,4156,1616,2328,

%U 1003,3106,312,536,3320,383,1470,528,375,3870,555,990,1278,1846,851

%N Let f(x,y)=floor((1+1/y)^x); sequence gives least k such that f(k+2,n)/f(k,n)=(1+1/n)^2.

%Y Cf. A065560.

%K nonn

%O 1,2

%A _Benoit Cloitre_, Apr 06 2003