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%I #12 May 20 2018 03:26:21
%S 1,1,1,1,2,1,1,3,3,1,1,2,6,2,1,1,5,10,10,5,1,1,6,15,10,15,6,1,1,7,21,
%T 35,35,21,7,1,1,2,14,14,70,14,14,2,1,1,3,6,42,42,42,42,6,3,1,1,10,15,
%U 30,210,42,210,30,15,10,1,1,11,55,165,330,462,462,330,165,55,11,1,1,6,66
%N Largest squarefree numbers dividing the binomial coefficients C(n,k) read by row, 0<=k<=n. Squarefree kernel of Pascal triangle.
%F a(n) = A007947(A007318(n)).
%e Triangle begins:
%e 1,
%e 1,1,
%e 1,2,1,
%e 1,3,3,1,
%e 1,2,6,2,1,
%e 1,5,10,10,5,1,
%e 1,6,15,10,15,6,1, ...
%o (PARI) T(n,k) = factorback(factorint(binomial(n,k))[, 1]);
%o tabl(nn) = for(n=0, nn, for (k=0, n, print1(T(n,k), ", ")); print); \\ _Michel Marcus_, May 20 2018
%Y Cf. A007318, A007947.
%K nonn,tabl
%O 0,5
%A _Labos Elemer_, Mar 19 2003
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