|
%I #7 Mar 30 2012 18:39:15
%S 1,2,3,6,6,8,7,11,12,13,14,21,21,23,29,28,26,31,37,36,36,42,45,48,51,
%T 47,50,53,53,62,57,55,55,68,69,52,63,66,71,79,63,66,78,90,83,82,78,85,
%U 80,91,91,90,92,93,93,107,110,103,119,120,113,115,118,121,125,125,130,135
%N Number of terms in the continued fraction for (Pi truncated to n decimal digits).
%e Pi truncated to 4 decimal places gives 3.1415 . The continued fraction for 3.1415 is [3, 7, 14, 1, 8, 2] which contains 6 terms, hence a(3)=6.
%Y Cf. A065019.
%K nonn,base
%O 0,2
%A _Benoit Cloitre_, Mar 17 2003
|
