A079359 Iterate the process: "sum of terms of n-th run" on the Kolakoski sequence until all runs have length 1.

1, 8, 1, 4, 1, 4, 6, 4, 1, 6, 1, 4, 8, 1, 4, 1, 8, 1, 4, 1, 8, 4, 1, 8, 1, 4, 8, 1, 4, 1, 8, 1, 8, 1, 4, 1, 4, 6, 4, 1, 6, 1, 4, 1, 4, 8, 1, 4, 6, 4, 1, 8, 4, 1, 8, 1, 4, 1, 8, 1, 4, 1

Offset

1,2

Comments

Is it enough to apply the process three times only to obtain all runs of length 1? Then all terms should have values among 1,4,6 or 8.

Links

Table of n, a(n) for n=1..62.

Example

Kolakoski sequence begins 1,2,2,1,1,2,1,2,2,1,2,2,1,1,2,1,1,2,2, When process is applied once: 1,2+2,1+1,2,1,2+2,1,2+2, --> 1,4,2,2,1,4,1,4,...Twice: 1,4,2+2,1,4...->1,4,4,1,4 ... Three times -> 1,8,1,4...

Crossrefs

Cf. A000002.

Sequence in context: A176457 A110194 A199283 * A010156 A197590 A154190

Adjacent sequences: A079356 A079357 A079358 * A079360 A079361 A079362

Keyword

nonn

Author

Benoit Cloitre, Feb 15 2003

Status

approved