

A078491


a(n) = lcm(1..Catalan(n)).


4




OFFSET

0,3


COMMENTS

For every cycle count LCMsequence Axxxxxx in A073204 it holds that Axxxxxx(n) divides a(n). And this also applies to similar LCMsequences induced by other "Catalan bijections", cf. A060113.


LINKS

Muniru A Asiru, Table of n, a(n) for n = 0..7
Index entries for sequences related to lcm's


FORMULA

a(n) = A003418(A000108(n)).


PROG

(PARI) a(n) = lcm([1..binomial(2*n, n)/(n+1)]); \\ Michel Marcus, Mar 21 2018
(GAP) List([0..7], n>Lcm([1..Binomial(2*n, n)/(n+1)])); # Muniru A Asiru, Mar 21 2018


CROSSREFS

Composition of the sequences A000108 and A003418.
Sequence in context: A078423 A231024 A121493 * A182856 A101896 A130411
Adjacent sequences: A078488 A078489 A078490 * A078492 A078493 A078494


KEYWORD

nonn


AUTHOR

Antti Karttunen, Jan 04 2003


STATUS

approved



