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A078491
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a(n) = lcm(1..Catalan(n)).
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4
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OFFSET
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0,3
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COMMENTS
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For every cycle count LCM-sequence Axxxxxx in A073204 it holds that Axxxxxx(n) divides a(n). And this also applies to similar LCM-sequences induced by other "Catalan bijections", cf. A060113.
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LINKS
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FORMULA
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MATHEMATICA
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Table[LCM@@Range[CatalanNumber[n]], {n, 0, 7}] (* Harvey P. Dale, Nov 21 2023 *)
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PROG
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(PARI) a(n) = lcm([1..binomial(2*n, n)/(n+1)]); \\ Michel Marcus, Mar 21 2018
(GAP) List([0..7], n->Lcm([1..Binomial(2*n, n)/(n+1)])); # Muniru A Asiru, Mar 21 2018
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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