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Table by antidiagonals where T(n,k)=sum_i T(floor[n/i],k-1) starting with T(n,0)=1 if n>0 and T(0,0)=0.
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%I #4 Mar 30 2012 18:51:39

%S 0,0,1,0,1,1,0,1,2,1,0,1,3,3,1,0,1,4,5,4,1,0,1,5,7,8,5,1,0,1,6,9,13,

%T 10,6,1,0,1,7,11,19,16,14,7,1,0,1,8,13,26,23,25,16,8,1,0,1,9,15,34,31,

%U 39,28,20,9,1,0,1,10,17,43,40,56,43,38,23,10,1,0,1,11,19,53,50,76,61,63

%N Table by antidiagonals where T(n,k)=sum_i T(floor[n/i],k-1) starting with T(n,0)=1 if n>0 and T(0,0)=0.

%F T(n, k) =T(n-1, k)+A077592(n, k). Writing m as sum_i p_i^e_i, T(n, k)= sum_m{1<=m<=n} product_i C(k+e_i-1, e_i).

%e Rows start: 0,0,0,0,0,0...; 1,1,1,1,1,1...; 1,2,3,4,5,6...; 1,3,5,7,9,11...; 1,4,8,13,19,26,...; etc.

%Y Columns include A057427, A001477, A006218, A061201, A061202, A061203, A061204. Rows include (with offsets) A000004, A000012, A000027, A005408, A034856, A052905. Cf. A077593.

%K nonn,tabl

%O 0,9

%A _Henry Bottomley_, Nov 08 2002