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%I #8 Jun 10 2018 21:12:24
%S 1,3,61,12201,2440201,4880402001,97608040020001,1952160800400020001,
%T 390432160080004000200001,780864320160008000400002000001,
%U 1561728640320016000800004000002000001,31234572806400320016000080000040000020000001
%N a(n) = (concatenation in ascending order of divisors of 5^n)/5^n.
%F a(0) = 1, a(n+1)) = 2*10^n*a(n) + 1.
%e a(5) = 15251256253125/3125 = 4880402001.
%o (PARI) a(n) = eval(concat(apply(x->Str(x),divisors(5^n))))/5^n \\ _Max Alekseyev_, Dec 12 2011
%Y Cf. A077351, A069872, A077352.
%K base,nonn
%O 0,2
%A _Amarnath Murthy_, Nov 05 2002
%E More terms from _Max Alekseyev_, Dec 12 2011
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