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First occurrence of n as a term in the continued fraction for zeta(2)=Pi^2/6.
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%I #6 Mar 30 2012 18:39:10

%S 1,6,12,5,37,23,8,56,83,14,107,128,111,121,20,171,346,172,57,45,607,

%T 641,968,925,239,291,44,659,396,233,186,1353,509,739,843,681,1020,213,

%U 577,345,670,196,287,91,54,3510,910,800,3462,803,503,355,3428,1157,247

%N First occurrence of n as a term in the continued fraction for zeta(2)=Pi^2/6.

%o (PARI) (15000 precision digits) v=contfrac(zeta(2)); a(n)=if(n<0,0,s=1; while(abs(n-component(v,s))>0,s++); s)

%Y Cf. A032523.

%K base,nonn

%O 1,2

%A _Benoit Cloitre_, Oct 20 2002