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%I #4 Mar 30 2012 18:50:26
%S 0,0,-1,0,1,-1,0,-8,-1,1,0,1,-1,-1,8,-47,1,-1,0,1,1,-1,-1,-16,1,-1,1,
%T 0,-1,-1,1,-1,-240,-1,1,1,1,-1,-1,1,1,-24,47,-1,0,-1,1,-1,1,-1,1,-1,
%U -1,24,1,-1,1,-1,1,1,-1,-1,-1,-1,1,1,-1,1,-1121,-1,0,1,-1,1,-1,1,1,-1,32,1,-1
%N A076341(A000961(n)), imaginary part of prime powers mapped as defined in A076340, A076341.
%e Applying the map as defined in A076340, A076341:
%e A000961(16)=27=3*3*3=(4-1)*(4-1)*(4-1) -> (4,-1)*(4,-1)*(4,-1) = (4*4-1,-8)*(4,-1) = (4*15-8,-32-15) = (52,-47), therefore a(16)=-47 and A076345(16)=52.
%Y Real part = A076345, A070750.
%K sign
%O 1,8
%A _Reinhard Zumkeller_, Oct 08 2002
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