%I #14 Jul 15 2022 09:59:46
%S 1,1,2,5,42,132,1144,3978,35530,690690,2731365,50067108,429757960,
%T 1822766520,15991836267,280086337895,4703540164785,21512315482350,
%U 360471372561300,3174207914954076,14859478810664136,248599618581498860,2209822117125283440,36246606227404101045
%N a(n) = binomial(prime(n),n)/prime(n) where prime(n) = n-th prime.
%C A prime p divides all the entries (binomial coefficients) in the p-th row of Pascal's triangle.
%F a(n) = A060604(n)/A000040(n).
%p seq(binomial(ithprime(n),n)/ithprime(n),n=1..30);
%t f[n_]:=Module[{pn=Prime[n]},Binomial[pn,n]/pn]
%t f/@Range[30] (* _Harvey P. Dale_, Feb 25 2011 *)
%o (PARI) a(n) = my(p=prime(n)); binomial(p, n)/p; \\ _Michel Marcus_, Jul 15 2022
%Y Cf. A060604, A000040.
%K nonn
%O 1,3
%A _Lekraj Beedassy_, Oct 16 2002
%E More terms from _Emeric Deutsch_, Mar 04 2004