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Numerator of 1/pp(n) + 1/pp(n+1), where pp(n) = A001597(n-1) is the n-th perfect power.
1

%I #8 Mar 08 2023 13:36:36

%S 5,3,17,25,41,52,59,17,85,113,145,181,221,246,253,17,313,365,103,49,

%T 52,499,545,613,667,704,761,841,925,249,1041,1105,1201,1301,1405,1513,

%U 1625,1741,1861,1961,253,2113,2245,2381,2521,2627,2700,2813,2965,3121

%N Numerator of 1/pp(n) + 1/pp(n+1), where pp(n) = A001597(n-1) is the n-th perfect power.

%e a(2) = 3 because 1/pp(2) + 1/pp(3) = 1/4 + 1/8 = 3/8.

%Y Cf. A001597.

%K easy,nonn,frac

%O 1,1

%A _Zak Seidov_, Oct 11 2002

%E Edited by _Dean Hickerson_, Oct 15 2002