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%I #5 Feb 23 2013 06:38:16
%S 2,3,5,6,8,8,9,9,11,11,11,11,12,12,14,13,14,13,14,14,13,14,15,15,14,
%T 15,15,16,14,15,15,16,16,17,16,16,16,15,18,17,18,16,17,16,17,17,17,17,
%U 18,17,18,18,17,18,17,19,19,17,19,18,20,18,18,19,18,19,19,18,20,19,19,21
%N Prime basis of A061373.
%C Since A061373 is pseudo-logarithmic with A061373(m*n)=A061373(m)+A061373(n) for m,n>1, its prime basis is sufficient to define it.
%F a(n)=A061373(A000040(n)), where p(n)=A000040(n) lists the primes. If p(n)-1 is written as product p(i)^e_i, then a(n) = 1 + sum a(i)*e_i.
%K nonn
%O 1,1
%A _Henry Bottomley_, Sep 04 2002
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