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A074783
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a(n) = floor(1/sin(x(n))) where x(n) is Pi truncated at the n-th decimal digit.
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1
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7, 24, 627, 1687, 10792, 376847, 1530011, 18660269, 278567575, 1695509434, 11136696004, 102111268281, 1260654956981, 10725187563685, 308788493220129, 4193528956200935, 25999253094360135, 118166387818704584
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OFFSET
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0,1
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COMMENTS
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a(n+1) = a(n) for n = 31, 49, 53, 64, 70, 76, 84, 96, 105, 115, 120, 127, ...
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LINKS
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FORMULA
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Is there a formula for lim m_{n -> oo} log(a(n))/n >= 2?
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EXAMPLE
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x(4)=3.1415 and 1/sin(x(4))=10792.889... hence a(4)=10792.
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PROG
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(PARI) a(n)=floor(1/sin(floor(Pi*10^n)/10^n))
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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