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1/n * sum over d|n of {mu(n/d) * (5d)! / d!^5}.
2

%I #5 Mar 30 2012 17:37:12

%S 120,56640,56055960,76385030400,124672148625000,228479027903507520,

%T 453922725503344566840,957089306644111555200000,

%U 2112293133628003412534448000,4833477575790121928875488600000

%N 1/n * sum over d|n of {mu(n/d) * (5d)! / d!^5}.

%H <a href="/index/Lu#Lyndon">Index entries for sequences related to Lyndon words</a>

%Y Inverse Witt transform of A006176. a(n) = A074657(n)*5.

%K nonn

%O 1,1

%A _Christian G. Bower_, Aug 28 2002