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a(n) = 3^n + 4^n + 5^n.
1

%I #16 Sep 08 2022 08:45:07

%S 3,12,50,216,962,4392,20450,96696,462722,2234952,10873250,53199576,

%T 261449282,1289406312,6376734050,31605668856,156925904642,

%U 780248462472,3883804162850,19349526496536,96470430052802,481245665067432

%N a(n) = 3^n + 4^n + 5^n.

%H Vincenzo Librandi, <a href="/A074547/b074547.txt">Table of n, a(n) for n = 0..200</a>

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (12,-47,60).

%F From _Mohammad K. Azarian_, Dec 28 2008: (Start)

%F G.f.: 1/(1-3*x) + 1/(1-4*x) + 1/(1-5*x).

%F E.g.f.: exp(3*x) + exp(4*x) + exp(5*x). (End)

%F a(n) = 12*a(n-1) - 47*a(n-2) + 60*a(n-3).

%t Table[3^n + 4^n + 5^n, {n, 0, 21}]

%o (Magma) [3^n + 4^n + 5^n: n in [0..30]]; // _Vincenzo Librandi_, Jun 13 2011

%Y Cf. A001550, A001576, A034513, A001579, A074501 - A074580.

%K easy,nonn

%O 0,1

%A _Robert G. Wilson v_, Aug 23 2002