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a(n) = 1^n + 7^n + 8^n.
0

%I #14 Jan 14 2018 23:06:51

%S 3,16,114,856,6498,49576,379794,2920696,22542018,174571336,1356217074,

%T 10567261336,82560763938,646644824296,5076269583954,39931933598776,

%U 314707907280258,2484430327672456,19642812107392434,155514083261229016

%N a(n) = 1^n + 7^n + 8^n.

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (16,-71,56).

%F From _Mohammad K. Azarian_, Dec 26 2008: (Start)

%F G.f.: 1/(1-x) + 1/(1-7*x) + 1/(1-8*x).

%F E.g.f.: e^x + e^(7*x) + e^(8*x). (End)

%F a(n) = 15*a(n-1) - 56*a(n-2) + 42 with a(0)=3, a(1)=16. - _Vincenzo Librandi_, Jul 21 2010

%t Table[1^n + 7^n + 8^n, {n, 0, 20}]

%Y Cf. A001550, A001576, A034513, A001579, A074501..A074580.

%K easy,nonn

%O 0,1

%A _Robert G. Wilson v_, Aug 23 2002