OFFSET
1,1
COMMENTS
The sequence of maximal sums begins 2, 4, 5, 7, 9, 10, 12, 13, 14, 16, 18, 19, 21, 23, 24, 25, 27, 28, 30, ...
LINKS
Hakan Icoz, Table of n, a(n) for n = 1..200
EXAMPLE
a(4)=6 because the Kolakoski sequence starting at position 6 is 2, 1, 2, 2 which sums to 7, which is the largest possible sum of 4 consecutive terms.
CROSSREFS
KEYWORD
nonn
AUTHOR
Jon Perry, Sep 21 2002
EXTENSIONS
a(8)-a(15) from and edited by Nathaniel Johnston, May 02 2011
More terms from Hakan Icoz, Jan 01 2022
STATUS
approved