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%I #5 Mar 31 2012 13:22:26
%S 5,13,17,23,29,34,41,48,52,59,67,71,78,85,91,97,103,109,115,121,125,
%T 131,137,143,149,157,161,168,175,179,185,191,196,202,209,217,221,227,
%U 233,239,245,251,256,263,268,274,280,286,292,298,304,311,319,323,329
%N Positions in the Kolakoski sequence A000002 when there are a multiple of 3 1's and the current term is 1.
%C n such that A000002(n) = 1 and A000002(m) = 1 for 3k indices m <= n, for some natural number k.
%H Nathaniel Johnston, <a href="/A074278/b074278.txt">Table of n, a(n) for n = 1..10000</a>
%e The Kolakoski sequence begins 1,2,2,1,1,2,1,2,2,1,2,2,1,1,2,... At position 5 and position 13, there are 3 and 6 1's, so 5 and 13 are in this sequence.
%Y Cf. A074273.
%K nonn,easy
%O 1,1
%A _Jon Perry_, Sep 21 2002
%E Extended and edited by _Nathaniel Johnston_, May 02 2011
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