|
%I #3 Oct 02 2013 16:02:48
%S 0,6,67,668,6695,66947,669467,6694672
%N Number of Fibonacci numbers F(k), k <= 10^n, whose initial digit is 6.
%F Lim as n -> inf. a(n)/10^n=log(7/6), where the base is 10. - _Robert Gerbicz_, Sep 05 2002
%e a(2)=6 because there are 6 Fibonacci numbers up to 10^2 whose initial digit is 6.
%K base,nonn
%O 1,2
%A _Shyam Sunder Gupta_, Aug 15 2002
%E More terms from _Robert Gerbicz_, Sep 05 2002
|
