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%I #18 Jan 27 2019 14:08:12
%S 2,3,28,5,0,7,225,153,640,11,6348,13,19474560,0,976,17,1225,19,1521,
%T 81,0,23,343000,49,2601,2133,3025,29,1495296000,31,20063232,4225,
%U 15262600,4761,19236456,37,25462407801600,5929,34633600,41,0,43,7569,356445,8281
%N Least m > 1 such that m^n has m divisors, or 0 if no such m exists.
%C Since a prime power p^k has exactly k+1 divisors, choosing k=p-1, where p is a prime, thus implies a(p-1)=p for any prime p.
%H Jon E. Schoenfield, <a href="/A073049/b073049.txt">Table of n, a(n) for n = 1..100</a>
%Y Cf. A000005, A323730.
%K nice,nonn
%O 1,1
%A _Lekraj Beedassy_, Aug 31 2002
%E Definition and terms for n = 1, 13, 23, 29, 31, 33, 35, 37, 39, and 44 corrected by _Jon E. Schoenfield_, Apr 17 2010