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Numerator of c(n) where c(0)=1, c(n+1) = n/c(n) + 1.
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%I #19 Dec 24 2020 21:24:13

%S 1,1,2,2,5,13,38,58,191,655,2374,4462,17519,71063,298810,646846,

%T 2887921,13237457,62332114,150303170,742458253,3748521653,19340144966,

%U 50903810666,273315477775,1495006933759,8327893878134,23599037077934

%N Numerator of c(n) where c(0)=1, c(n+1) = n/c(n) + 1.

%H Roberto Dvornicich, Francesco Veneziano, and Umberto Zannier, <a href="http://arxiv.org/abs/1403.3470">On the integral values of a curious recurrence</a>, arXiv:1403.3470 [math.NT], 2014.

%H <a href="/index/O#Olympiads">Index to sequences related to Olympiads</a>.

%F It seems that log(a(n)) is asymptotic to C*n*Log(n) with C=0.4....

%o (PARI) lista(nn) = {my(x = 1); for (n=0, nn, print1(numerator(x), ", "); x = 1+ n/x;);} \\ _Michel Marcus_, Dec 24 2020

%Y Cf. A072899.

%K easy,frac,nonn

%O 0,3

%A _Benoit Cloitre_, Aug 10 2002

%E a(0)=1 prepended by _Michel Marcus_, Dec 24 2020