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%I #6 Nov 21 2013 12:47:50
%S 1,12,23,265,276,529,6084,6095,6348,12167,139921,139932,140185,146004,
%T 279841,3218172,3218183,3218436,3224255,3358092,6436343,74017945,
%U 74017956,74018209,74024028,74157865,77236116,148035889,1702412724
%N The terms of A073215 (sums of two powers of 23) divided by 2.
%F (23^n + 23^m) / 2, n = 0, 1, 2, 3 ..., m = 0, 1, 2, 3, ... n.
%e a(4) = 265 = (23^2+23^0) / 2
%t Union[#/2&/@(Total/@Tuples[23^Range[0,7],{2}])] (* _Harvey P. Dale_, Apr 21 2011 *)
%Y Cf. A073215.
%K easy,nonn
%O 1,2
%A _Jeremy Gardiner_, Jul 21 2002
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