OFFSET
1,1
COMMENTS
p^2 and 2p^2 are always in inverse set, so a(n) >= 2.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
Max Alekseyev, PARI/GP Scripts for Miscellaneous Math Problems (invphi.gp).
FORMULA
a(n) = Card[InvPhi(p(n)*(p(n)-1))] = Card[InvPhi(A036689(n))].
EXAMPLE
For n = 5: prime(5) = 11, a(5) = 2 because InvPhi(110) = {121, 242}.
For n = 6: prime(6) = 13, a(6) = 7 because InvPhi(13*12) = InvPhi(156) = {157, 169, 237, 314, 316, 338, 474}.
MAPLE
[seq(nops(invphi(ithprime(j)*(-1+ithprime(j)))), j=1..128)];
PROG
(PARI) a(n) = my(p=prime(n)); #invphi(p*(p-1)); \\ Michel Marcus, Mar 25 2020
CROSSREFS
KEYWORD
nonn
AUTHOR
Labos Elemer, Jun 04 2002
STATUS
approved
