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Successive minima of partial sum of harmonic series Sum (mu(n)/n) are approximately 1/a(n).
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%I #17 Mar 28 2021 00:14:37

%S 2,6,-30,-105,-2310,-6860,6922,-6955,-7021,-192857,-201094,-220036,

%T -679269,-736738,-762102,-2538828,-2621491,-3325700,-6146329,-9601104,

%U -9659740,-10027087,-10355141,-220990748

%N Successive minima of partial sum of harmonic series Sum (mu(n)/n) are approximately 1/a(n).

%e a(3) = 30 because the third successive minimum is (1 - 1/2 - 1/3 - 1/5) = -1/(30).

%o (PARI) t = 0.; t1 = 1; v = []; for( n = 1, 200, t = t + moebius(n)/n; if( ( t/t1)^2 < 1, t1 = t; v = concat( v, floor( 1/t)), )); v

%Y Cf. A008683.

%K sign

%O 1,1

%A _Donald S. McDonald_, May 18 2002

%E More terms from _Donald S. McDonald_, verified by _Sean A. Irvine_, Sep 30 2018