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Determinant of the 2n X 2n matrix m(i,j) = i^j - j^i.
2

%I #10 Apr 18 2024 10:28:02

%S 1,1,196,65028096,1540115470208876544,

%T 861787404007697994335390269440000,

%U 3024149801599872168810739614376506649075557335040000,25610879735369429335666530857036523659955793212506655095941286757767577600000000

%N Determinant of the 2n X 2n matrix m(i,j) = i^j - j^i.

%C Determinant of the (2n+1) X (2n+1) matrix m(i,j) = i^j-j^i is zero.

%t Join[{1}, Table[Det[Table[i^j - j^i, {i, 1, 2*n}, {j, 1, 2*n}]], {n, 1, 8}]] (* _Vaclav Kotesovec_, Apr 18 2024 *)

%o (PARI) for(n=1,20,print1(matdet(matrix(2*n,2*n,i,j,i^j-j^i)),","))

%K easy,nonn

%O 0,3

%A _Benoit Cloitre_, May 28 2002

%E a(0)=1 prepended by _Alois P. Heinz_, Jan 25 2023