%I #8 Dec 15 2012 13:26:56
%S 1,2,3,16,4,37,5,16,38,49,6,44,40,29,50,16,7,51,9,49,30,40,15,44,8,40,
%T 52,56,36,50,23,43,41,26,20,81,43,9,41,49,16,73,11,40,51,29,63,44,34,
%U 49,225,40,224,196,27,56,10,36,45,50,126,23,74,193,279,41,76,26,30,56
%N Smallest integer k such that n divides floor((3/2)^k).
%C a(n)=n for some n = 1,2,3,16,56,283,....Conjectures : (i) Log(n) < a(n) < n*Log(n)^2 for n>6; (ii) the equation a(x)=n always has a solution.
%H Harvey P. Dale, <a href="/A070973/b070973.txt">Table of n, a(n) for n = 1..1000</a>
%F a(n) = min( k : A002379(k) == 0 mod(n) )
%t sik[n_]:=Module[{k=1},While[!Divisible[Floor[(3/2)^k],n],k++];k]; Array[sik,70] (* _Harvey P. Dale_, Dec 15 2012 *)
%o (PARI) for(n=1,100,s=1; while(floor((3/2)^s)%n>0,s++); print1(s,","))
%Y Cf. A002379.
%K easy,nonn
%O 1,2
%A _Benoit Cloitre_, May 24 2002