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a(n) = n^6 mod 39.
0

%I #18 Jun 30 2026 22:30:14

%S 0,1,25,27,1,25,12,25,25,27,1,25,27,13,1,12,1,1,12,25,25,12,1,1,12,1,

%T 13,27,25,1,27,25,25,12,25,1,27,25,1,0,1,25,27,1,25,12,25,25,27,1,25,

%U 27,13,1,12,1,1,12,25,25,12,1,1,12,1,13,27,25,1,27,25,25,12,25,1,27,25

%N a(n) = n^6 mod 39.

%H <a href="/index/Rec#order_39">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%F a(n) = a(n-39). - _Wesley Ivan Hurt_, Dec 26 2023

%t PowerMod[Range[0, 80], 6, 39] (* _Harvey P. Dale_, Aug 28 2016 *)

%t (* Alternative: *)

%t PadRight[{},120,{0,1,25,27,1,25,12,25,25,27,1,25,27,13,1,12,1,1,12,25,25,12,1,1,12,1,13,27,25,1,27,25,25,12,25,1,27,25,1}] (* _Harvey P. Dale_, Aug 28 2016 *)

%o (SageMath) [power_mod(n,6,39)for n in range(0, 77)] # _Zerinvary Lajos_, Nov 07 2009

%o (PARI) a(n)=n^6%39 \\ _Charles R Greathouse IV_, Apr 06 2016

%K nonn,easy,changed

%O 0,3

%A _N. J. A. Sloane_, May 13 2002