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a(n) = n^6 mod 25.
0

%I #24 Dec 26 2023 21:20:29

%S 0,1,14,4,21,0,6,24,19,16,0,11,9,9,11,0,16,19,24,6,0,21,4,14,1,0,1,14,

%T 4,21,0,6,24,19,16,0,11,9,9,11,0,16,19,24,6,0,21,4,14,1,0,1,14,4,21,0,

%U 6,24,19,16,0,11,9,9,11,0,16,19,24,6,0,21,4,14,1,0,1,14,4,21,0,6,24,19

%N a(n) = n^6 mod 25.

%C Periodic, with period 25: 0, 1, 14, 4, 21, 0, 6, 24, 19, 16, 0, 11, 9, 9, 11, 0, 16, 19, 24, 6, 0, 21, 4, 14, 1. - _Harvey P. Dale_, Oct 14 2014

%H <a href="/index/Rec#order_25">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%F a(n) = a(n-25). - _Wesley Ivan Hurt_, Dec 26 2023

%t PowerMod[Range[0,100],6,25] (* _Harvey P. Dale_, Oct 14 2014 *)

%o (Sage) [power_mod(n,6,25) for n in range(0, 84)] # _Zerinvary Lajos_, Nov 06 2009

%o (Magma) [n^6 mod 25: n in [0..80]]; // _Vincenzo Librandi_, Oct 15 2014

%o (PARI) a(n)=n^6%25 \\ _Charles R Greathouse IV_, Apr 06 2016

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, May 13 2002